F(0)=2x^2-5x+9

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Solution for F(0)=2x^2-5x+9 equation: 



(0)=2F^2-5F+9

We move all terms to the left:

(0)-(2F^2-5F+9)=0

We add all the numbers together, and all the variables

-(2F^2-5F+9)=0

We get rid of parentheses

-2F^2+5F-9=0

a = -2; b = 5; c = -9;
Δ = b2-4ac
Δ = 52-4·(-2)·(-9)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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